X^2-20x+100=16

Solution for X^2-20x+100=16 equation:

X^2-20X+100=16

We move all terms to the left:

X^2-20X+100-(16)=0

We add all the numbers together, and all the variables

X^2-20X+84=0

a = 1; b = -20; c = +84;
Δ = b2-4ac
Δ = -202-4·1·84
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-8}{2*1}=\frac{12}{2}
=6
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+8}{2*1}=\frac{28}{2}
=14
$